By testing eof() instead of eof in dave0's one-liner, you can extend its functionality to sum across multiple files. Like this:
# First we make to test files
% perl -le 'print join(",", map int(rand(1000)), 1..10) for 1..50' > i
+n1.csv
% perl -le 'print join(",", map int(rand(1000)), 1..10) for 1..50' > i
+n2.csv
% head -3 in1.csv
94,434,249,267,649,367,572,579,498,369
452,735,420,543,832,198,28,86,67,382
801,339,978,859,85,719,758,89,191,377
# Now we run dave0's original script on them
perl -lanF, -e '$sum += $F[6]; print "Sum is $sum" if eof' in1.csv in2
+.csv
Sum is 23789
Sum is 48874
# Now let's try a small change --------------------------.
# |
# V
perl -lanF, -e '$sum += $F[6]; print "Sum is $sum" if eof()' in1.csv i
+n2.csv
Sum is 48874
What happens is that
eof (no parens!) returns true at the end of each file in @ARGV, while
eof() is true only at the end of the last one (see
eof). In the case of a single input file, the behavior is the same as before.
To get subtotals, you'd do
perl -lanF, -e '$total += $F[6]; $sub += $F[6]; print "Subtotal: $sub"
+ and $sub = 0 if eof; print "Total: $total" if eof()' in1.csv in2.csv
Subtotal: 23789
Subtotal: 25085
Total: 48874
An alternative to testing for eof(), is to put everything in an END. e.g.
perl -lanF, -e '$sum += $F[6]; END{ print "Sum is $sum" }' in1.csv in2
+.csv
Update: Bug in last one-liner corrected.
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