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@array[0 ..0] is one and not zero elements!

DB<103> @array=a..f => ("a", "b", "c", "d", "e", "f") DB<104> @array[0..0] => "a"


your statistical proof falls into the trap

scalar @array != scalar (LIST)

if your function() returns a one element list (0), then scalar function() will be 0, since 0 is the last element of the list.

(more detailed in Re^2: Idiom to return 0 or random number of array elements by eyepopslikeamosquito )

initializing @array = 1..10 makes it more obvious, b/c the last element of a sublist is now identical to the length!

DB<106> @array = 1 .. 10; => (1, 2, 3, 4, 5, 6, 7, 8, 9, 10) DB<107> sub x{ return @array[ 0 .. int( rand @array ) ]; }; => 0 DB<108> $stats{ scalar( x() ) }++ for 1 .. 1000; => "" DB<109> \%stats; => { 1 => 100, 2 => 101, 3 => 108, 4 => 108, 5 => 101, 6 => 103, 7 => + 79, 8 => 98, 9 => 100, 10 => 102 }

Cheers Rolf

In reply to Re^2: Idiom to return 0 or random number of array elements by LanX
in thread Idiom to return 0 or random number of array elements by Anonymous Monk

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