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> "sub foo {}" doesn't count as a run-time statment.
Ah I see! Now this explains why wrapping with do {... } helps. > $ say '$^D=$^D; (); sub foo {}' Good idea! I'll do that, thanks!
Cheers Rolf ( addicted to the Perl Programming Language) In reply to Re^2: Hacking Debugger bugs connected to $^D (())
by LanX
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