I should have been clearer its the choice of ipaddress to return that's the issue.
If I return all addresses it get it in a reverse order than a C# program (both are copied below). if I use Khen1950fx's first example I get the answer as 192.168.0.1 which is the wrong address to use. Code that picks the first address to use now breaks down on a multiadapter machines.
Outputs via C# and perl
>listaddrcsharp.exe
10.123.67.139
192.168.0.1
>perl d:\temp\in.pl
192.168.0.1
10.123.67.139
Perl code
use Socket;
use IO::Socket;
my $machineName = lc($ENV{COMPUTERNAME});
my ($name, $aliases, $addrtype, $length, @addrs) = gethostbyname($mach
+ineName);
foreach(@addrs)
{
($a,$b,$c,$d)=unpack ('C4', $_);
print "$a.$b.$c.$d\n";
}
C# Code
public static void Main(string[] args)
{
IPAddress[] ips;
ips = Dns.GetHostAddresses(Environment.MachineName);
foreach (IPAddress ip in ips)
{
if (ip.AddressFamily == AddressFamily.InterNetwork)
Console.WriteLine(" {0}", ip);
}
}
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