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> Consider the relative difficulty of fixing your problem case vs. my counter-factual problem case:

while(  $x  = shift @a ) {    # Fixed

this is not a fix because while stops, if any element of @a is false.

DB<187> @a=(1,undef,2,3,0,4,5) DB<188> print $x while $x =shift @a 1 DB<189> print $x while $x =shift @a 23 DB<190> print $x while $x =shift @a 45 DB<191> print $x while $x =shift @a

Thats the old semipredicate problem, which can only be solved with list-assignments.

But I agree with you that it's most probably too late to fix that design decision...

Cheers Rolf

( addicted to the Perl Programming Language)

) for completeness: no defined doesn't help here, if undef is a legal value.

  • corrected "semipredicate problem"
  • improved code example
  • your "better" update is indeed better

) best answer so far

In reply to Re^2: shift in list context buggy? (best answer so far!) by LanX
in thread shift in list context buggy? by LanX

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