http://www.perlmonks.org?node_id=78776


in reply to LFSR golf

How about 
sub l{my($s,$t)=@_;sub {($s=($s.(((my $x=$s+$t)=~y/1/1/d)%9%2)))=~s/5.
+/5/;$s}}
$x=l("50101","0022");print ($x->(),$x->(),$x->(),$x->());

[download]
The first line is the generating sub (containing 79 chars) and the second one is an usage example.

Replies are listed 'Best First'.
73 chars, called on a foul (Re: LFSR golf)
by tye (Sage) on May 08, 2001 at 18:32 UTC

    I don't mind the departure in how you call the generating function but I'm going to disqualify this one for having the closure return "50101" instead of 0 and "51100" instead of 1.

    If you were shifting the other direction, then a simple &1 at the end of the closure would solve the problem and give you a 73-character solution (not counting the "sub l{" and "}", as usual).

    I'm sure this general approach can be modified such that I'd accept it but I'll leave that to you or whoever beats you to it. (:

            - tye (but my friends call me "Tye")
[reply]
[d/l]
      Didn't know you wanted that. OK. New version (72 chars) 
      sub l{
my($s,$t)=@_;sub{($s=($s.(((my$x=$s+$t)=~y/1/1/d)%9%2)))=~s/5(.)/5/;$1
+}
}
 $x=l("50101","0022");print ($x->(),$x->(),$x->(),$x->());

      [download]
[reply]
[d/l]

In Section Meditations