See, you need one of us old-timers for this kind of stuff. ;-)
In all likelihood, a Fortran program is producing that data. The variable in the program is declared DOUBLE PRECISION, and probably a D or G format is being used to print it. Just substitute E for D and you should be fine.
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Surely, surely, those 'D's have to mean 'E's... well, of course they don't have to, but if you have to add 30 to one of those numbers, then you have to know what the original number is, right?
So that's a piece of data you need someone to inform you of. If it is an exponent indicator, then can you just do a pattern match before interpreting the number (s/D/E/)?
Rob
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Maybe I'm missing something...
What I don't get is that the addition is performed correctly despite the "D" instead of "E".
$my_x = $info[4] + 0;
$my_y = $info[5] + 30;
for($i = '1'; $i <= $info[2]; $i++) {
print ("$my_x $my_y $info[($i + 8)]\n");
$my_y = $my_y + 30;
I would expect to see for the output:
0.22512 30.341916 661
but it actually does understand D+06 as exponential notation
Can anyone explain why?
Thanks,
Kris | [reply] [d/l] [select] |