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Re^3: Correct way to use Net:SSH2 module

by salva (Abbot)
on Mar 21, 2013 at 09:30 UTC ( #1024691=note: print w/ replies, xml ) Need Help??


in reply to Re^2: Correct way to use Net:SSH2 module
in thread Correct way to use Net:SSH2 module

No, the documentation says you can not reuse a channel once it has been closed. But you can open several channels, even in parallel, over the same connection.

BTW, you should also check Net::SSH::Any.


Comment on Re^3: Correct way to use Net:SSH2 module
Re^4: Correct way to use Net:SSH2 module
by MikeKulls2 (Novice) on Mar 21, 2013 at 22:30 UTC
    Sorry, I misread your code, I see that you are creating a new channel for each call. The function being called channel instead of createChannel or newChannel threw me :-) With regards my original question, if I connect with shell instead of exec would I be correct in saying there is no way to tell when the end of the response has been received? Why does it not return the prompt? Also, with your code, why does a poll time of 500ms work perfectly well with a command like "ls;sleep 5;ls;"? When I reduce the poll time to 100ms it times out.
      Sorry, I misread your code
      My code? I suppose you mean GrandFather code in Re: Correct way to use Net:SSH2 module!

      if I connect with shell instead of exec would I be correct in saying there is no way to tell when the end of the response has been received?

      Yes, if you run a shell, you have to use some heuristic as looking for the prompt or delaying for a while to detect or ensure that the command is done.

      why does a poll time of 500ms work perfectly well with a command like "ls;sleep 5;ls;"? When I reduce the poll time to 100ms it times out

      Because that code is broken!

      As the SSH object is not set to work in non-blocking mode, once some data becomes available in the channel the code gets stuck in the inner loop where read is called until the channel is closed by the remote side. Then, it runs again the outer loop where it gets the channel_closed event and exits.

      When the timeout is set to 100ms, sometimes it will expire before any data from the first ls command arrives and so never entering the inner loop.

        Oh yes, I meant GrandFather's code. I guess the answer is that shell is for humans and programming against it will always be flawed. The number of ways it can fail is quite extensive, eg differences between OSes, differences between versions of the same OS, path not setup correctly, different environment settings etc. With regards to the code being flawed I was wondering the same thing. Basically the only thing stopping it locking up is that the channel is closed.

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