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perl oneliners

by valavanp (Curate)
on Aug 19, 2006 at 08:35 UTC ( [id://568328]=perlquestion: print w/replies, xml ) Need Help??

valavanp has asked for the wisdom of the Perl Monks concerning the following question:

I want to replace 3 instances of file path in a directory by using perl oneliner. This is the command which i gave and worked well.

perl -e 's/\/usr\/bin\/perl/\/test\/test\/test/g;s/\/ggg\/ggg\/www/\/z +zz\/zzz\/zzz/g;s/\/jjj\/jjj\/jjj/\/aaa\/aaa\/aaa/g;' -pi *.pl

But when i include this oneliner in a separate file called script.pl i am getting compilations errors here is how i have given;

#!/usr/local/bin/perl use strict; use warnings; perl -e 's/\/usr\/bin\/perl/\/test\/test\/test/g;s/\/ggg\/ggg\/www/\/z +zz\/zzz\/zzz/g;s/\/jjj\/jjj\/jjj/\/aaa\/aaa\/aaa/g;' -pi *.pl print "Done";

The following error occurred for me when i compile this.

syntax error at script.pl line 8, near "perl -e " script.pl had compilation errors

Can anyone tell me where i am wrong? Thanks monks for your valuable suggestion.

Replies are listed 'Best First'.
Re: perl oneliners
by shmem (Chancellor) on Aug 19, 2006 at 08:45 UTC
    You invoke your code as oneliner like this
    perl -e 's/\/usr\/bin\/perl/\/test\/test\/test/g;s/\/ggg\/ggg\/www/\/z +zz\/zzz\/zzz/g;s/\/jjj\/jjj\/jjj/\/aaa\/aaa\/aaa/g;' -pi *.pl

    and in a script

    #!/usr/local/bin/perl -pi use strict; use warnings; s/\/usr\/bin\/perl/\/test\/test\/test/g; s/\/ggg\/ggg\/www/\/zzz\/zzz\/zzz/g; s/\/jjj\/jjj\/jjj/\/aaa\/aaa\/aaa/g; END { print "Done\n"; }

    with this line:

    perl script.pl *.pl

    update: To avoid backslashitis, you could write your s/// as, e.g., s|||:

    s|/usr/bin/perl|/test/test/test|g; s|/ggg/ggg/www|/zzz/zzz/zzz|g; s|/jjj/jjj/jjj|/aaa/aaa/aaa|g;

    --shmem

    _($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                                  /\_¯/(q    /
    ----------------------------  \__(m.====·.(_("always off the crowd"))."·
    ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
      Thanks shmem for your reply. It works well. But this script.pl file also gets changed. I wanted to keep this in the main directory and want to run the .pl files in the test directory. I am using suse linux os. the directory path is /main/script.pl -- Script file. /main/test/*.pl files -- perl files. In the oneliners there is an option like this $(find .-type f). How can i do this in the script file. Thanks for your reply.
        This case, just use the shell:
        perl -i -e 's|/usr/bin/perl|/test/test/test|g;s|/ggg/ggg/www|/zzz/zzz/ +zzz|g;s|/jjj/jjj/jjj|/aaa/aaa/aaa|g; ' /main/script.pl `find /path/to +/pl/files/ -type f`
        FYI, there's File::Find in the standard perl distribution ... and i personally like File::Find::Rule
        But this script.pl file also gets changed... the directory path is /main/script.pl -- Script file. /main/test/*.pl files -- perl files.

        Let's suppose you write your script file like this (I prefer using curly braces around regexes when the slash is part of the pattern or replacement):

        #!/usr/bin/perl use strict; use warnings; # check for valid usage (user must provide a directory path): (@ARGV == 1 and -d $ARGV[0]) or die "Usage: $0 /path/to/scripts\n"; my $path = shift; { local $/; # set input record separator to undef (slurp-mode read +ing) for my $file (<$path/*.pl>) # use a file glob { open( F, "<", $file ) or next; $_ = <F>; close F; s{/usr/bin/perl}{/test/test/test}g; s{/ggg/ggg/www}{/zzz/zzz/zzz}g; s{/jjj/jjj/jjj}{/aaa/aaa/aaa}g; open( F, ">", $file ) or die "$file: $!"; print F; close F; } }
        When you put that script file in a directory other than the one that you provide as a command-line arg when you run it (or if you put it in the same directory, but give it a name that does not end in ".pl"), the script will not edit/rewrite itself.

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