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Hi All, How can I print a "\n" in between two different strings, cache and DISK.* where they appear twice.

__INPUT__
cache,23778,0.0,0,0.0,0,0.0,0.0,0.00
cache,205,0.0,0,0.0,0,0.0,0.0,0.00
DISK-UTIL-PEAK-HIGH:,54.3,DISK-UTIL:,2.5
PROC-Name,PID,PYS-IO-RATE,READs,READ-RATE,WRITEs
cache,26094,0.9,1,0.9,0,0.0,0.0,0.00
cache,16046,0.0,0,0.0,0,0.0,0.0,0.00
cache,3848,0.0,0,0.0,0,0.0,0.0,0.00
cache,23778,0.0,0,0.0,0,0.0,0.0,0.00
cache,205,0.0,0,0.0,0,0.0,0.0,0.00
DISK-UTIL-PEAK-HIGH:,54.3,DISK-UTIL:,3.4  ### last line ###
__END__

use strict;
use warnings;

my $dstattmp = qq(/usr/local/log/disk.gpm.statlog.tmp);
my $dstatlog = qq(/usr/local/log/disk.gpm.statlog.csv);

open( my $DT, "+>>", $dstatlog ) || die "$dstatlog was not opened $!";
open( my $TD, "+>",  $dstattmp ) || die "$dstattmp was not opened $!";

while (<$DT>) {
    next if ( $. == 1);
    if ( /cache|disk-.*/i ) {
        push my @tmp, split;
        print $TD join (",", @tmp),"\n";
    }

    if ( /^(\D.*)(?=\d*)(?=disk-util-peak.*)/i )
        print $TD "YES\n";
    }
    ##if ( /^(cache.*)(?=\d*)(?=disk-util-peak.*)/i )
    ##if ( /^(cache.*)(?=\d*)/ .. /disk-util-peak.*/igs )  
} 

thank you!
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In reply to regexp look behind? by dbs

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