Re: regex: negative lookahead

[kennethk]

in reply to regex: negative lookahead

If you take a look at what you have in $1 after your failed miss for 2, the issue will become more apparent, I think; print $1; yields log4j.rootLogger=INFO, FILE, SYSLOG. Essentially, you have already consumed ", SYSLOG" by the time you get to the end of the string, so clearly that bit does not follow. A negative look-behind will actually yield what you intended:

print "has_matched $has\n" if $has =~ /^($start(\w+(,\s)?)+)(?<!$end)$/;

[svenXY]

Hi,
++kennethk - thanks for clarifying. I'm still a little bit confused by the difference between (?!...) and (?<!...) though.
Regards,
svenXY

[kennethk]

The difference is a lookahead versus a lookbehind. If you ignore the lookahead/lookbehind because they are zero width (don't consume characters), you would expect /^($start(\w+(,\s)?)+)$/ to grab an entire string between start and finish. When you get to the part of the regular expression where you have your assertion, the cursor is here:

log4j.rootLogger=INFO, FILE, SYSLOG
                                   ^

If you look ahead of this position, there is nothing, which clearly passes the negative lookahead check. The offending string is behind your position, thus you need a negative lookbehind.