Re: extract file name from path

[keszler]

my $line = "root 30145 1 0 Jan30 ? 00:09:01 /root/java/app/java_app_1R
+ule_java_app_2Rule.java --javaproc";
$line =~ m{.*/([^ ]+)}; # update - fixed typo of '/' to close regex
my $id = $1;

perlretut