using stat

[Anonymous Monk]

Dear monks,

I have a file that I need to find the permissions and file type for. However, I have a small problem with it. I do not see the permissions or type, just numbers. Here is the code:

$fileMode = (stat $dirItem)[2];

Here is a sample number I get back from a file: 33279

How do I convert the numbers into type and permissions? I am using Windows NT.

Thanks for any help

[jdporter]

Using stat to get file permissions info on Windows isn't going to give you very much useful, because permissions are managed in a completely different way than on Unix, which is where stat comes from.
Instead, check out the Win32::FileSecurity module for methods to get useful info on Windows.

jdporter
The 6th Rule of Perl Club is -- There is no Rule #6.

[LD2]

check out this documentation

here's an example from it:

Because the mode contains both the file type and its permissions, you 
+should mask off the file type portion and (s)printf using a "%o" if y
+ou want to see the real permissions.

    $mode = (stat($filename))[2];
    printf "Permissions are %04o\n", $mode & 07777;In scalar context, 
+stat returns a boolean value indicating success or failure, and, if s
+uccessful, sets the information associated with the special filehandl
+e _.

The File::stat module provides a convenient, by-name access mechanism:

    use File::stat;
    $sb = stat($filename);
    printf "File is %s, size is %s, perm %04o, mtime %s\n", 
        $filename, $sb->size, $sb->mode & 07777,
        scalar localtime $sb->mtime;