Re: ^\s not equal \S?

[Anonymous Monk]

Welcome to Boolean Algebra!

[^\s\w] = NOT (space OR word)
[\S\W] = (NOT space) OR (NOT word)

(NOT space) OR (NOT word) = NOT (space AND word)

[delirium]

Well, I finally did it. I ++'d an anonymous post. Good answer. I was going to say something like:

[^\s\w] means neither spaces nor words, or, everything but spaces and words, where
[\S\W] means non-spaces AND non-words, and since a space is a non-word, the meaning is similar to "non-spaces and spaces".

However, ^\s and \S should be the same, so...

$phrase =~ s/[^\s*\w*]//g;

would do the same thing as...


$phrase =~ s/[\S]|[\W]|[^*]//g;

Update: No, it wouldn't. :: smacks self in head ::

[SavannahLion]