comment on

I like Grandfather's solution. It uses the scalar value of grep in an "if" statement and the simplicity of this is normally the best way to go. If @array is very big, here is one way to stop processing once you have a "match". This speeds things up at the cost of complexity.

#!usr/bin/perl -w
use strict;

my @array=(34,52,67,3,66);

is_value_gt_min_array_element(5,\@array) ? 
               print "yes, 5 is  greater than @array\n"
             : print "no,  5 isn't greater than: @array\n";

                                          
is_value_gt_min_array_element(3,\@array) ? 
               print "yes, 3 is  greater than @array\n"
             : print "no,  3 isn't greater than: @array\n";
                                          
                                          
is_value_gt_min_array_element(2,\@array) ? 
               print "yes, 2 is  greater than @array\n"
             : print "no,  2 isn't greater than: @array\n";

sub is_value_gt_min_array_element
{
   my ($value, $arrayref) = @_;
   foreach (@$arrayref)
   {
      return 1 if ($value > $_); #this is a "found it!"
                                 #stop searching for another one
   }
   return 0;
}

print "There are ", scalar(grep{$_>3}@array), " numbers ",
      "greater than 3 in: @array\n"; 

      
__END__
prints:
yes, 5 is  greater than 34 52 67 3 66
no,  3 isn't greater than: 34 52 67 3 66
no,  2 isn't greater than: 34 52 67 3 66
There are 4 numbers greater than 3 in: 34 52 67 3 66
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In reply to Re: Check if at least one element of array is bigger than X by Marshall
in thread Check if at least one element of array is bigger than X by Anonymous Monk

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