comment on

Yeah, I thought about that and completely agree with you - I was just reusing that ksh script someone else had written - I replaced that with:

sub dbConnect(){
   my ($dbName) = @_;

   LogStatus "Retrieving $dbName login info";

   my ($dbUser, $dbPass) = get_db_login($dbName);

   LogStatus "User for $dbName is $dbUser";

   die "$0: Could not find password for $dbUser" unless(defined($dbPas
+s));

   my $dbh = DBI->connect("dbi:DB2:$dbName", $dbUser, $dbPass, {AutoCo
+mmit=> 0, RaiseError => 1})
      || die "Can't connect to $database: $DBI::errstr";

   LogStatus "Connected to $dbName as $dbUser";

   return $dbh;
}

sub get_db_login {
    my ($dbName) = @_;
    my ($dbUser, $dbPass, $whoami);

    chomp($whoami = `whoami`);

    open(PASSWD,"/home/$whoami/.passwd") or die "~/.passwd does not ex
+ist";
    while(<PASSWD>){
        if($_=~/^$dbName\s+(\w+)\s+(\w+)/i){
            $dbUser = $1;
            $dbPass = $2;
        }
    }
    close PASSWD;

    return $dbUser, $dbPass;
}
[download]

Unfortunately, I am still getting the same behavior as I never see the result of:

LogStatus "User for $dbName is $dbUser";

In reply to Re^2: backtick operator by Anonymous Monk
in thread backtick operator by spjcr

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